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Beliebt Rechnen >

y^{''}+14*2y^'+49y=0,y(0)=0,y^'(0)=1

Lösung

y^{^{''}} + 14 \cdot 2 y^{^{'}} + 49 y = 0, y (0) = 0, y^{^{'}} (0) = 1

Lösung

y = \frac{1}{14 3} e^{7 (3 - 2) t} - \frac{1}{14 3} e^{- 7 (2 + 3) t}

Schritte zur Lösung

y^{''} (t) + 14 \cdot 2 y^{'} (t) + 49 y = 0

Solve linear ODE:

y = \frac{1}{14 3} e^{7 (3 - 2) t} - \frac{1}{14 3} e^{- 7 (2 + 3) t}

y = \frac{1}{14 3} e^{7 (3 - 2) t} - \frac{1}{14 3} e^{- 7 (2 + 3) t}

Graph

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