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Frequently Asked Questions (FAQ)
What is the solution for -8t^2y^{''}-4t(t-4)y^'+4(t-4)y=0 ?
- The solution for -8t^2y^{''}-4t(t-4)y^'+4(t-4)y=0 is y=c_{1}t+c_{2}e^{-t/2}t