derivative of 2x^4-6x^3-12x-8

解答

\frac{d}{d x} (2 x^{4} - 6 x^{3} - 12 x - 8)

8 x^{3} - 18 x^{2} - 12

求解步骤

\frac{d}{d x} (2 x^{4} - 6 x^{3} - 12 x - 8)

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{4}) - \frac{d}{d x} (6 x^{3}) - \frac{d}{d x} (12 x) - \frac{d}{d x} (8)

\frac{d}{d x} (2 x^{4}) = 8 x^{3}

\frac{d}{d x} (6 x^{3}) = 18 x^{2}

\frac{d}{d x} (12 x) = 12

\frac{d}{d x} (8) = 0

= 8 x^{3} - 18 x^{2} - 12 - 0

化简

= 8 x^{3} - 18 x^{2} - 12

n = 5 \sum \infty \frac{1}{n ( n - 1 )}

\int_{2}^{4} (x^{4} - 1) d x

x \to 0 lim ((1 + 4 x)^{\frac{6}{x}})

\frac{\partial}{\partial y} (3 x^{2} y + 5 x y^{3})

d er i v a t i v e \frac{( 3 - x )}{4 x}