(\partial)/(\partial x)((m^2)/(4xy))

解答

\frac{\partial}{\partial x} (\frac{m ^{2}}{4 x y})

- \frac{m ^{2}}{4 x ^{2} y}

求解步骤

\frac{\partial}{\partial x} (\frac{m ^{2}}{4 x y})

将

m, y

视为常数

将常数提出:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{m ^{2}}{4 y} \frac{\partial}{\partial x} (\frac{1}{x})

使用指数法则:

\frac{1}{a} = a^{- 1}

= \frac{m ^{2}}{4 y} \frac{\partial}{\partial x} (x^{- 1})

使用幂法则:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{m ^{2}}{4 y} (- 1 \cdot x^{- 1 - 1})

化简

\frac{m ^{2}}{4 y} (- 1 \cdot x^{- 1 - 1}) : - \frac{m ^{2}}{4 x ^{2} y}

= - \frac{m ^{2}}{4 x ^{2} y}

\frac{d}{d x} (arcsin (1))

x \to 2 lim (2 x - \frac{1}{x})

\int_{- 1}^{1} (x^{2} + 6 x)^{3} (2 x + 6) d x

\int_{1}^{9} \frac{1}{x x ^{2} + 9} d x

t a y l or \frac{1}{1 + 2 x}