What is the derivative of f(-1)=(x+3)/2 ?

The derivative of f(-1)=(x+3)/2 is 1/2

What is the first derivative of f(-1)=(x+3)/2 ?

The first derivative of f(-1)=(x+3)/2 is 1/2

derivative of

f (- 1) = \frac{x + 3}{2}

\frac{1}{2}

Decimal

0.5

Solution steps

\frac{d}{d x} (\frac{x + 3}{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{d}{d x} (x + 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{2} (\frac{d x}{d x} + \frac{d}{d x} (3))

\frac{d x}{d x} = 1

\frac{d}{d x} (3) = 0

= \frac{1}{2} (1 + 0)

Simplify

= \frac{1}{2}

\frac{\partial}{\partial x} (ln (1 - x - y) - x^{- 1} - y^{- 1})

d er i v a t i v e f (x) = e^{- 5 x}

d er i v a t i v e y = x + 10

in v erse l a pl a ce \frac{( 5 )}{s ^{2} - 9}

l a pl a ce t r an s f or m t^{3} + 3 t^{2} + 3 t + 1

What is the derivative of f(-1)=(x+3)/2 ?
The derivative of f(-1)=(x+3)/2 is 1/2
What is the first derivative of f(-1)=(x+3)/2 ?
The first derivative of f(-1)=(x+3)/2 is 1/2