en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular Calculus >

area y=2x,y=2x^2-4

Solution

area

y = 2 x, y = 2 x^{2} - 4

Solution

9

Solution steps

Apply the area formula:

\int_{- 1}^{2} 2 x - (2 x^{2} - 4) d x

Solve

\int_{- 1}^{2} 2 x - (2 x^{2} - 4) d x : 9

The area is:

= 9

Graph

Popular Examples

derivative of |2x+1|

\frac{d}{d x} (∣ 2 x + 1 ∣)

integral from 1 to 8 of 2/(x^3)

\int_{1}^{8} \frac{2}{x ^{3}} d x

(\partial)/(\partial x)((\sqrt[7]{x})^4)

\frac{\partial}{\partial x} ((7 x)^{4})

limit as x approaches 0+of (-ln(x))^x

x \to 0 + lim ((- ln (x))^{x})

(dy)/(dx)=((3x^2))/(y^2)

\frac{d y}{d x} = \frac{( 3 x ^{2} )}{y ^{2}}

Frequently Asked Questions (FAQ)

What is area y=2x,y=2x^2-4 ?
The answer to area y=2x,y=2x^2-4 is 9