integral of (5x+3)/(x^2+1)

Lösung

\int \frac{5 x + 3}{x ^{2} + 1} d x

\frac{5}{2} ln x^{2} + 1 + 3 arctan (x) + C

Schritte zur Lösung

\int \frac{5 x + 3}{x ^{2} + 1} d x

Multipliziere aus

\frac{5 x + 3}{x ^{2} + 1} : \frac{5 x}{x ^{2} + 1} + \frac{3}{x ^{2} + 1}

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{5 x}{x ^{2} + 1} d x + \int \frac{3}{x ^{2} + 1} d x

\int \frac{5 x}{x ^{2} + 1} d x = \frac{5}{2} ln x^{2} + 1

\int \frac{3}{x ^{2} + 1} d x = 3 arctan (x)

= \frac{5}{2} ln x^{2} + 1 + 3 arctan (x)

Füge eine Konstante zur Lösung hinzu

= \frac{5}{2} ln x^{2} + 1 + 3 arctan (x) + C

n = 1 \sum \infty 1 9^{n} x^{n} n!

x \to - 2 + lim (\frac{- 6 x}{x + 2})

\int \frac{x}{x ^{4} + 2 x ^{2} + 1} d x

\frac{\partial}{\partial x} (ln (x^{4} + y^{4}) - z)

\frac{\partial}{\partial x} (\frac{3}{x ^{3}})