What is inverse oflaplace 3-2/(s-1) ?

The answer to inverse oflaplace 3-2/(s-1) is 3\delta(t)-2e^t

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

inverse oflaplace 3-2/(s-1)

inverse laplace

3 - \frac{2}{s - 1}

3 δ (t) - 2 e^{t}

Solution steps

L^{- 1} {3 - \frac{2}{s - 1}}

Use the linearity property of Inverse Laplace Transform:

For functions

f (s), g (s)

and constants

a, b : L^{- 1} {a \cdot f (s) + b \cdot g (s)} = a \cdot L^{- 1} {f (s)} + b \cdot L^{- 1} {g (s)}

= L^{- 1} {3} - L^{- 1} {\frac{2}{s - 1}}

L^{- 1} {3} : 3 δ (t)

L^{- 1} {\frac{2}{s - 1}} : 2 e^{t}

= 3 δ (t) - 2 e^{t}

a re a x^{2} - 6 x + 9, x^{2} - x + 6, [0, 5]

t \frac{d y}{d t} = t^{3} + 6 t^{3} y

x \to 0 + lim (x (12))

\int_{a}^{3 a} x d x

a re a x - 2, x, 0, 4

What is inverse oflaplace 3-2/(s-1) ?
The answer to inverse oflaplace 3-2/(s-1) is 3\delta(t)-2e^t