integral of 3x+6

Lösung

\int 3 x + 6 d x

\frac{3 x ^{2}}{2} + 6 x + C

Schritte zur Lösung

\int 3 x + 6 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 x d x + \int 6 d x

\int 3 x d x = \frac{3 x ^{2}}{2}

\int 6 d x = 6 x

= \frac{3 x ^{2}}{2} + 6 x

Füge eine Konstante zur Lösung hinzu

= \frac{3 x ^{2}}{2} + 6 x + C

\int y^{2} (4 - y^{3})^{\frac{2}{3}} d y

\frac{\partial}{\partial x} (x^{2} \frac{y}{x ^{4} + y ^{2}})

a re a x^{4} + x^{3}, x^{4} + x^{2} + 6 x

y^{^{''}} - 3 y^{^{'}} + 2 y = 0, y (0) = 0, y^{^{'}} (0) = 0

\frac{d}{d x} (\frac{9 - x ^{2}}{8 x})