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Popular Calculus >

y^'+2xy=xy^2

Solution

y^{^{'}} + 2 x y = x y^{2}

Solution

y = \frac{2}{e ^{x^{2} + c_{1}} + 1}

Solution steps

y^{'} (x) + 2 x y = x y^{2}

Solve Bernoulli ODE:

y = \frac{2}{e ^{x^{2} + c_{1}} + 1}

y = \frac{2}{e ^{x^{2} + c_{1}} + 1}

Graph

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x \to 1 lim (sin (\frac{π}{2} x))

Frequently Asked Questions (FAQ)

What is the solution for y^'+2xy=xy^2 ?
The solution for y^'+2xy=xy^2 is y= 2/(e^{x^2+c_{1)}+1}