(\partial)/(\partial x)(x^2y^2+4x^2-3xy)

Lösung

\frac{\partial}{\partial x} (x^{2} y^{2} + 4 x^{2} - 3 x y)

2 y^{2} x + 8 x - 3 y

Schritte zur Lösung

\frac{\partial}{\partial x} (x^{2} y^{2} + 4 x^{2} - 3 x y)

Behandle

y

als Konstante

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2} y^{2}) + \frac{\partial}{\partial x} (4 x^{2}) - \frac{\partial}{\partial x} (3 x y)

\frac{\partial}{\partial x} (x^{2} y^{2}) = 2 y^{2} x

\frac{\partial}{\partial x} (4 x^{2}) = 8 x

\frac{\partial}{\partial x} (3 x y) = 3 y

= 2 y^{2} x + 8 x - 3 y

f^{^{''}} (x) = a cos (2 x) + b sin (2 x)

n = 1 \sum \infty 3 (\frac{1}{4})^{n - 1}

\int \frac{( x ^{3} )}{( 1 + x ^{2} )} d x

d er i v a t i v e f (- x) = \frac{x}{x ^{2} + 1}

\int \frac{1}{x ^{2} - 361} d x