(\partial)/(\partial x)(sqrt(6-x^2-y^2))

解答

\frac{\partial}{\partial x} (6 - x^{2} - y^{2})

- \frac{x}{6 - x ^{2} - y ^{2}}

求解步骤

\frac{\partial}{\partial x} (6 - x^{2} - y^{2})

将

y

视为常数

使用连锁律:

\frac{1}{2 6 - x ^{2} - y ^{2}} \frac{\partial}{\partial x} (6 - x^{2} - y^{2})

= \frac{1}{2 6 - x ^{2} - y ^{2}} \frac{\partial}{\partial x} (6 - x^{2} - y^{2})

\frac{\partial}{\partial x} (6 - x^{2} - y^{2}) = - 2 x

= \frac{1}{2 6 - x ^{2} - y ^{2}} (- 2 x)

化简

\frac{1}{2 6 - x ^{2} - y ^{2}} (- 2 x) : - \frac{x}{6 - x ^{2} - y ^{2}}

= - \frac{x}{6 - x ^{2} - y ^{2}}

t an g e n t f (x) = x^{3} - 5 x^{2}

\int_{- 2}^{0} x^{2} e^{x^{3} + 8} d x

\int \frac{2}{1 + cos ( 2 x )} d x

\int \frac{arctan ( x )}{x ^{2} + 1} d x

t a y l or e^{x}, 2