derivative of Cx+C-C^2

解答

\frac{d}{d x} (C x + C - C^{2})

C

求解步骤

\frac{d}{d x} (C x + C - C^{2})

将

C

视为常数

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (C x) + \frac{d C}{d x} - \frac{d}{d x} (C^{2})

\frac{d}{d x} (C x) = C

\frac{d C}{d x} = 0

\frac{d}{d x} (C^{2}) = 0

= C + 0 - 0

化简

= C

x^{3} y^{^{'''}} - 2 x^{2} y^{^{''}} + 13 x y^{^{'}} - 13 y = 0

a re a y = \frac{3}{x}, y = \frac{3}{x ^{2}}, x = 5

\int \frac{sec ^{2} ( x )}{tan ^{2} ( x ) - 1} d x

x \to 0 lim (csc (x) + cot (x))

t an g e n t f (x) = 2 x^{3} - 2 x^{2} + 8, (3, 44)