integral of (4x+3)

Lösung

\int (4 x + 3) d x

2 x^{2} + 3 x + C

Schritte zur Lösung

\int 4 x + 3 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 4 x d x + \int 3 d x

\int 4 x d x = 2 x^{2}

\int 3 d x = 3 x

= 2 x^{2} + 3 x

Füge eine Konstante zur Lösung hinzu

= 2 x^{2} + 3 x + C

\frac{\partial}{\partial y} ((x^{2} + y^{2}) e^{- y})

\frac{\partial}{\partial u} (3 v sin (u))

\frac{d}{d x} (\frac{2 ^{x}}{x})

x \to 0 lim (\frac{( 5 ^{x} - 7 ^{x} )}{x})

\frac{d}{d x} ((- 2 x^{3} + x^{2} - 2 x - 1) x^{3})