What is the limit as x approaches 0-of 3/(1+e^{1/x)} ?

The limit as x approaches 0-of 3/(1+e^{1/x)} is 3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches 0-of 3/(1+e^{1/x)}

x \to 0 - lim (\frac{3}{1 + e ^{\frac{1}{x}}})

3

Solution steps

x \to 0 - lim (\frac{3}{1 + e ^{\frac{1}{x}}})

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= 3 \cdot x \to 0 - lim (\frac{1}{1 + e ^{\frac{1}{x}}})

x \to a lim [\frac{f ( x )}{g ( x )}] = \frac{lim _{x \to a} f ( x )}{lim _{x \to a} g ( x )}, x \to a lim g (x) \neq = 0

With the exception of indeterminate form

= 3 \cdot \frac{lim _{x \to 0 -} ( 1 )}{lim _{x \to 0 -} ( 1 + e ^{\frac{1}{x}} )}

x \to 0 - lim (1) = 1

x \to 0 - lim (1 + e^{\frac{1}{x}}) = 1

= 3 \cdot \frac{1}{1}

Simplify

= 3

\int x (7 - x)^{2} d x

1 + x

\int 6 x - 5 d x

\int 5 x^{4} d x

\frac{d y}{d x} + \frac{y}{x} = y^{- 2}

What is the limit as x approaches 0-of 3/(1+e^{1/x)} ?
The limit as x approaches 0-of 3/(1+e^{1/x)} is 3