What is the integral of (x^3+3)x^2 ?

The integral of (x^3+3)x^2 is (x^6)/6+x^3+C

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integral of (x^3+3)x^2

\int (x^{3} + 3) x^{2} d x

\frac{x ^{6}}{6} + x^{3} + C

Solution steps

\int (x^{3} + 3) x^{2} d x

Expand

(x^{3} + 3) x^{2} : x^{5} + 3 x^{2}

= \int x^{5} + 3 x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{5} d x + \int 3 x^{2} d x

\int x^{5} d x = \frac{x ^{6}}{6}

\int 3 x^{2} d x = x^{3}

= \frac{x ^{6}}{6} + x^{3}

Add a constant to the solution

= \frac{x ^{6}}{6} + x^{3} + C

What is the integral of (x^3+3)x^2 ?
The integral of (x^3+3)x^2 is (x^6)/6+x^3+C