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Beliebt Rechnen >

y^'=0.5-t+2y,y(0)=1

Lösung

y^{^{'}} = 0.5 - t + 2 y, y (0) = 1

Lösung

y = \frac{t}{2} + e^{2 t}

Schritte zur Lösung

y^{'} (t) = 0.5 - t + 2 y

Solve linear ODE:

y = \frac{t}{2} + e^{2 t}

y = \frac{t}{2} + e^{2 t}

Graph

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