What is the derivative of 2/3 x^3-3/(4x^2) ?

The derivative of 2/3 x^3-3/(4x^2) is 2x^2+3/(2x^3)

What is the first derivative of 2/3 x^3-3/(4x^2) ?

The first derivative of 2/3 x^3-3/(4x^2) is 2x^2+3/(2x^3)

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\frac{d}{d x} (\frac{2}{3} x^{3} - \frac{3}{4 x ^{2}})

2 x^{2} + \frac{3}{2 x ^{3}}

Solution steps

\frac{d}{d x} (\frac{2}{3} x^{3} - \frac{3}{4 x ^{2}})

Simplify

\frac{2}{3} x^{3} - \frac{3}{4 x ^{2}} : \frac{2 x ^{3}}{3} - \frac{3}{4 x ^{2}}

= \frac{d}{d x} (\frac{2 x ^{3}}{3} - \frac{3}{4 x ^{2}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{2 x ^{3}}{3}) - \frac{d}{d x} (\frac{3}{4 x ^{2}})

\frac{d}{d x} (\frac{2 x ^{3}}{3}) = 2 x^{2}

\frac{d}{d x} (\frac{3}{4 x ^{2}}) = - \frac{3}{2 x ^{3}}

= 2 x^{2} - (- \frac{3}{2 x ^{3}})

Simplify

= 2 x^{2} + \frac{3}{2 x ^{3}}

d er i v a t i v e y = sin (tan (5 x))

\int (t^{9} + 4 t) (9 t^{8} + 4) d t

\int (4 x - \frac{2}{x}) d x

\int \frac{2}{( x - 3 ) ^{2}} d x

f (x) = x^{3} e^{- x^{3}} + 5

What is the derivative of 2/3 x^3-3/(4x^2) ?
The derivative of 2/3 x^3-3/(4x^2) is 2x^2+3/(2x^3)
What is the first derivative of 2/3 x^3-3/(4x^2) ?
The first derivative of 2/3 x^3-3/(4x^2) is 2x^2+3/(2x^3)