What is the derivative of 2x+8/x ?

The derivative of 2x+8/x is 2-8/(x^2)

What is the first derivative of 2x+8/x ?

The first derivative of 2x+8/x is 2-8/(x^2)

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\frac{d}{d x} (2 x + \frac{8}{x})

2 - \frac{8}{x ^{2}}

Solution steps

\frac{d}{d x} (2 x + \frac{8}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) + \frac{d}{d x} (\frac{8}{x})

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (\frac{8}{x}) = - \frac{8}{x ^{2}}

= 2 - \frac{8}{x ^{2}}

\frac{\partial}{\partial y} (x + 2 y - 22)

a re a y = x - 3, y = - x - 1, x = 1, x = 3

t a y l or x^{\frac{9}{6}}, 8

d er i v a t i v e (9 - x^{3})^{5}

\int \frac{4}{5} - \frac{9}{x} d x

What is the derivative of 2x+8/x ?
The derivative of 2x+8/x is 2-8/(x^2)
What is the first derivative of 2x+8/x ?
The first derivative of 2x+8/x is 2-8/(x^2)