What is the tangent of y=5+5x^2-2x^3,(1,8) ?

The tangent of y=5+5x^2-2x^3,(1,8) is y=4x+4

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tangent of y=5+5x^2-2x^3,(1,8)

tangent of

y = 5 + 5 x^{2} - 2 x^{3}, (1, 8)

y = 4 x + 4

Solution steps

Find the slope of

y = 5 + 5 x^{2} - 2 x^{3} : \frac{d y}{d x} = - 6 x^{2} + 10 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 4

Find the line with slope m=

4

and passing through

(1, 8) : y = 4 x + 4

y = 4 x + 4

x \to \infty lim (\frac{2}{3 x})

\int 10000 (t - 6) d t

\int 5 x sin (x) d x

d er i v a t i v e 14 x

f (x) = e^{l n (c o s (x^{2}))} 2 x + 1

What is the tangent of y=5+5x^2-2x^3,(1,8) ?
The tangent of y=5+5x^2-2x^3,(1,8) is y=4x+4