integral from 10 to 20 of (10)/(x^2)

Lösung

\int_{10}^{20} \frac{10}{x ^{2}} d x

\frac{1}{2}

Dezimale

0.5

Schritte zur Lösung

\int_{10}^{20} \frac{10}{x ^{2}} d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 10 \cdot \int_{10}^{20} \frac{1}{x ^{2}} d x

Wende die Potenzregel an

= 10 [- \frac{1}{x}]_{10}^{20}

Berechne die Grenzen:

\frac{1}{20}

= 10 \cdot \frac{1}{20}

Vereinfache

= \frac{1}{2}

\int 4 x^{2} (4 x^{3} - x^{2})^{6} d x

y^{^{''}} + y^{^{'}} - 6 y = t e^{2 t}

\frac{\partial}{\partial x} (1 + \frac{2}{y})

\int_{0}^{34} (2 x - x^{2}) d x

x^{2} \frac{d ^{2} y}{d x ^{2}} - 7 x \frac{d y}{d x} + 16 y = 0