What is the derivative of 17e^x-ex^e ?

The derivative of 17e^x-ex^e is 17e^x-e^2x^{e-1}

What is the first derivative of 17e^x-ex^e ?

The first derivative of 17e^x-ex^e is 17e^x-e^2x^{e-1}

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derivative of

17 e^{x} - e x^{e}

17 e^{x} - e^{2} x^{e - 1}

Solution steps

\frac{d}{d x} (17 e^{x} - e x^{e})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (17 e^{x}) - \frac{d}{d x} (e x^{e})

\frac{d}{d x} (17 e^{x}) = 17 e^{x}

\frac{d}{d x} (e x^{e}) = e^{2} x^{e - 1}

= 17 e^{x} - e^{2} x^{e - 1}

\frac{\partial}{\partial x} (e^{- x} sin (yz))

t an g e n t f (x) = 2 x^{5} - 6 x^{3}, at x = 1

\int ln (d) x d x

x \to 3 lim (\frac{x - 1}{x ^{2}})

a re a y = x^{2} + x - 2, y = 0

What is the derivative of 17e^x-ex^e ?
The derivative of 17e^x-ex^e is 17e^x-e^2x^{e-1}
What is the first derivative of 17e^x-ex^e ?
The first derivative of 17e^x-ex^e is 17e^x-e^2x^{e-1}