What is the sum from n=4 to infinity of 1/(n^2) ?

The sum from n=4 to infinity of 1/(n^2) is converges

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sum from n=4 to infinity of 1/(n^2)

n = 4 \sum \infty \frac{1}{n ^{2}}

converges

Solution steps

n = 4 \sum \infty \frac{1}{n ^{2}}

Apply p-Series Test:

converges

= converges

t an g e n t f (x) = \frac{6}{5 x + 2}, (- 1, - 2)

\int (\frac{sin ( 4 x )}{4}) - (\frac{sin ^{3} ( x )}{4}) d x

n = 0 \sum \infty n (n + 1) - 1

\int cos (x + π) d x

in v erse l a pl a ce \frac{e ^{- s}}{s ^{2} ( s + 2 )}

What is the sum from n=4 to infinity of 1/(n^2) ?
The sum from n=4 to infinity of 1/(n^2) is converges