What is the integral from 1 to 9 of pi(x-1) ?

The integral from 1 to 9 of pi(x-1) is 32pi

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integral from 1 to 9 of pi(x-1)

\int_{1}^{9} π (x - 1) d x

32 π

Decimal

100.53096 \dots

Solution steps

\int_{1}^{9} π (x - 1) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= π \cdot \int_{1}^{9} x - 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= π (\int_{1}^{9} x d x - \int_{1}^{9} 1 d x)

\int_{1}^{9} x d x = 40

\int_{1}^{9} 1 d x = 8

= π (40 - 8)

Simplify

= 32 π

t an g e n t f (x) = \frac{5}{x}, (5, 1)

d er i v a t i v e \frac{( x - 1 )}{x ^{2} + 3}

\int \frac{1}{( 9 - x ^{2} ) ^{\frac{3}{2}}} d x

\int_{0}^{2} x e^{- 5 x} d x

\int \frac{x + 5}{x ^{2} + 11 x + 18} d x

What is the integral from 1 to 9 of pi(x-1) ?
The integral from 1 to 9 of pi(x-1) is 32pi