What is the integral of 1/2 x^{-2} ?

The integral of 1/2 x^{-2} is -1/(2x)+C

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integral of 1/2 x^{-2}

\int \frac{1}{2} x^{- 2} d x

- \frac{1}{2 x} + C

Solution steps

\int \frac{1}{2} x^{- 2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int x^{- 2} d x

Apply the Power Rule

= \frac{1}{2} (- \frac{1}{x})

Simplify

\frac{1}{2} (- \frac{1}{x}) : - \frac{1}{2 x}

= - \frac{1}{2 x}

Add a constant to the solution

= - \frac{1}{2 x} + C

\frac{d}{d x} (e^{x + 6})

f (x) = ln (x^{2} + 5)

\frac{d}{d x} (tan (x^{2}) + tan^{2} (x))

y^{^{'}} - 2 y = e^{3 t}

d er i v a t i v e - \frac{6}{x}