What is the derivative of ln(x^2+10) ?

The derivative of ln(x^2+10) is (2x)/(x^2+10)

What is the first derivative of ln(x^2+10) ?

The first derivative of ln(x^2+10) is (2x)/(x^2+10)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

\frac{d}{d x} (ln (x^{2} + 10))

\frac{2 x}{x ^{2} + 10}

Solution steps

\frac{d}{d x} (ln (x^{2} + 10))

Apply the chain rule:

\frac{1}{x ^{2} + 10} \frac{d}{d x} (x^{2} + 10)

= \frac{1}{x ^{2} + 10} \frac{d}{d x} (x^{2} + 10)

\frac{d}{d x} (x^{2} + 10) = 2 x

= \frac{1}{x ^{2} + 10} \cdot 2 x

Simplify

\frac{1}{x ^{2} + 10} \cdot 2 x : \frac{2 x}{x ^{2} + 10}

= \frac{2 x}{x ^{2} + 10}

\frac{d}{d t} (10000 (12 + t) e^{- 0.05 t})

\int \frac{5}{( 3 x - 1 )} d x

\frac{d}{d x} (e^{60 x + 50 x^{2}})

\frac{d y}{d x} = \frac{y ^{3} - x ^{3}}{x y ^{2}}

d er i v a t i v e 2 lo g_{5} (x)

What is the derivative of ln(x^2+10) ?
The derivative of ln(x^2+10) is (2x)/(x^2+10)
What is the first derivative of ln(x^2+10) ?
The first derivative of ln(x^2+10) is (2x)/(x^2+10)