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人気のある微分積分 >

integral from 0 to 1 of 2pi(x)(9-8x-x^2)

解

\int_{0}^{1} 2 π (x) (9 - 8 x - x^{2}) d x

解

\frac{19 π}{6}

+1

十進法表記

9.94837 \dots

解答ステップ

\int_{0}^{1} 2 π x (9 - 8 x - x^{2}) d x

定数を除く:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 π \cdot \int_{0}^{1} x (9 - 8 x - x^{2}) d x

拡張

x (9 - 8 x - x^{2}) : 9 x - 8 x^{2} - x^{3}

= 2 π \cdot \int_{0}^{1} 9 x - 8 x^{2} - x^{3} d x

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 2 π (\int_{0}^{1} 9 x d x - \int_{0}^{1} 8 x^{2} d x - \int_{0}^{1} x^{3} d x)

\int_{0}^{1} 9 x d x = \frac{9}{2}

\int_{0}^{1} 8 x^{2} d x = \frac{8}{3}

\int_{0}^{1} x^{3} d x = \frac{1}{4}

= 2 π (\frac{9}{2} - \frac{8}{3} - \frac{1}{4})

簡素化

2 π (\frac{9}{2} - \frac{8}{3} - \frac{1}{4}) : \frac{19 π}{6}

= \frac{19 π}{6}

グラフ

人気の例

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