What is the derivative of f(x)=(2x+7)^2 ?

The derivative of f(x)=(2x+7)^2 is 4(2x+7)

What is the first derivative of f(x)=(2x+7)^2 ?

The first derivative of f(x)=(2x+7)^2 is 4(2x+7)

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derivative of

f (x) = (2 x + 7)^{2}

4 (2 x + 7)

Solution steps

\frac{d}{d x} ((2 x + 7)^{2})

Apply the chain rule:

2 (2 x + 7) \frac{d}{d x} (2 x + 7)

= 2 (2 x + 7) \frac{d}{d x} (2 x + 7)

\frac{d}{d x} (2 x + 7) = 2

= 2 (2 x + 7) \cdot 2

Simplify

= 4 (2 x + 7)

d er i v a t i v e - 16 t^{2}

x^{4} \frac{d y}{d x} + 2 x^{3} y = 1

\frac{d}{d x} (\frac{1}{4 - x})

d er i v a t i v e f (x) = \frac{sin ( x ) - x}{x ^{2}}

\int \frac{x}{4 - x ^{2}} d x

What is the derivative of f(x)=(2x+7)^2 ?
The derivative of f(x)=(2x+7)^2 is 4(2x+7)
What is the first derivative of f(x)=(2x+7)^2 ?
The first derivative of f(x)=(2x+7)^2 is 4(2x+7)