sqrt(1-3x^2)y^'=x

Lösung

1 - 3 x^{2} y^{^{'}} = x

y = - \frac{1}{3} 1 - 3 x^{2} + c_{1}

Schritte zur Lösung

1 - 3 x^{2} y^{'} (x) = x

Isoliere

y^{'} (x) : y^{'} (x) = \frac{x}{1 - 3 x ^{2}}

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

y = \int \frac{x}{1 - 3 x ^{2}} d x

\int \frac{x}{1 - 3 x ^{2}} d x = - \frac{1}{3} 1 - 3 x^{2} + c_{1}

y = - \frac{1}{3} 1 - 3 x^{2} + c_{1}

\frac{\partial}{\partial y} (e^{x^{2} - y^{2} + 4 y})

x \to 1 lim (\frac{x ^{3} - x}{1 - x})

\frac{d}{d x} ((x^{2} + 2 y^{2} + 3 z^{2}) e^{- (x^{2} + y^{2} + z^{2})})

d er i v a t i v e 6 cos (sin (x^{2}))

\frac{d}{d x} (ln (1 + 0))