What is the solution for x4+y3sqrt(x)5+2y^'=0 ?

The solution for x4+y3sqrt(x)5+2y^'=0 is y=(integral of-2e^{5x^{3/2}}x)/(e^{5x^{3/2)}}

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x4+y3sqrt(x)5+2y^'=0

x 4 + y 3 x 5 + 2 y^{^{'}} = 0

y = \frac{\int - 2 e ^{5 x^{\frac{3}{2}}} x d x}{e ^{5 x^{\frac{3}{2}}}}

Solution steps

x 4 + y 3 x 5 + 2 y^{'} (x) = 0

Solve linear ODE:

y = \frac{\int - 2 e ^{5 x^{\frac{3}{2}}} x d x}{e ^{5 x^{\frac{3}{2}}}}

y = \frac{\int - 2 e ^{5 x^{\frac{3}{2}}} x d x}{e ^{5 x^{\frac{3}{2}}}}

\frac{d}{d x} (e^{3 x} + b)

\int x^{2} 3 x + 3 d x

\frac{d}{d x} (4 x^{2} - x)

\int 4 x (2 x^{2} + 1)^{8} d x

t an g e n t f (x) = x^{2} - 5, at x = 1

What is the solution for x4+y3sqrt(x)5+2y^'=0 ?
The solution for x4+y3sqrt(x)5+2y^'=0 is y=(integral of-2e^{5x^{3/2}}x)/(e^{5x^{3/2)}}