What is the derivative of f(x)=sqrt((1-x)/(1+x)) ?

The derivative of f(x)=sqrt((1-x)/(1+x)) is -1/(sqrt(-x+1)(x+1)^{3/2)}

What is the first derivative of f(x)=sqrt((1-x)/(1+x)) ?

The first derivative of f(x)=sqrt((1-x)/(1+x)) is -1/(sqrt(-x+1)(x+1)^{3/2)}

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derivative of

f (x) = \frac{1 - x}{1 + x}

- \frac{1}{- x + 1 ( x + 1 ) ^{\frac{3}{2}}}

Solution steps

\frac{d}{d x} (\frac{1 - x}{1 + x})

Apply the chain rule:

\frac{1}{2 \frac{1 - x}{1 + x}} \frac{d}{d x} (\frac{1 - x}{1 + x})

= \frac{1}{2 \frac{1 - x}{1 + x}} \frac{d}{d x} (\frac{1 - x}{1 + x})

\frac{d}{d x} (\frac{1 - x}{1 + x}) = - \frac{2}{( 1 + x ) ^{2}}

= \frac{1}{2 \frac{1 - x}{1 + x}} (- \frac{2}{( 1 + x ) ^{2}})

Simplify

\frac{1}{2 \frac{1 - x}{1 + x}} (- \frac{2}{( 1 + x ) ^{2}}) : - \frac{1}{- x + 1 ( x + 1 ) ^{\frac{3}{2}}}

= - \frac{1}{- x + 1 ( x + 1 ) ^{\frac{3}{2}}}

t an g e n t f (x) = x^{2} + 15, at x = 7

\frac{\partial}{\partial x} (arctan (\frac{y}{x}))

d er i v a t i v e \frac{6}{5 x + 3}

\int \frac{1}{( x + 1 )} d x

5 y^{^{'}} = 2 y

What is the derivative of f(x)=sqrt((1-x)/(1+x)) ?
The derivative of f(x)=sqrt((1-x)/(1+x)) is -1/(sqrt(-x+1)(x+1)^{3/2)}
What is the first derivative of f(x)=sqrt((1-x)/(1+x)) ?
The first derivative of f(x)=sqrt((1-x)/(1+x)) is -1/(sqrt(-x+1)(x+1)^{3/2)}