(\partial)/(\partial x)(xyz-e^z)

解答

\frac{\partial}{\partial x} (x yz - e^{z})

yz

求解步骤

\frac{\partial}{\partial x} (x yz - e^{z})

将

y, z

视为常数

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x yz) - \frac{\partial}{\partial x} (e^{z})

\frac{\partial}{\partial x} (x yz) = yz

\frac{\partial}{\partial x} (e^{z}) = 0

= yz - 0

化简

= yz

(x^{2} - y x^{2}) d y + y^{2} (1 + x) d x = 0

\frac{\partial}{\partial t} (x + y sin (t))

\int t^{2} - 9 d t

\int (3 x^{2} + 4 x + 2) d x

\frac{d}{d x} (\frac{48}{( 1 - 2 x ) ^{4}})