f^'=f^3

Lösung

f^{^{'}} = f^{3}

f (t) = - \frac{1}{2 ( t + c _{1} )}, f (t) = - - \frac{1}{2 ( t + c _{1} )}

Schritte zur Lösung

f^{'} (t) = f (t)^{3}

Solve separable ODE:

f (t) = - \frac{1}{2 ( t + c _{1} )}, f (t) = - - \frac{1}{2 ( t + c _{1} )}

f (t) = - \frac{1}{2 ( t + c _{1} )}, f (t) = - - \frac{1}{2 ( t + c _{1} )}

\frac{d}{d x} (x^{- 2} ln (x))

\int_{1}^{4} \frac{x}{x ^{2} + 6 x + 13} d x

\frac{\partial}{\partial x} (arctan (3 x))

x \to \infty lim (\frac{4 x ^{6} - x}{x ^{3} + 2})

x \to \infty lim (2 x e^{- 2 x})