y^{''}-6y^'-16y=0

Lösung

y^{^{''}} - 6 y^{^{'}} - 16 y = 0

y = c_{1} e^{8 t} + c_{2} e^{- 2 t}

Schritte zur Lösung

y^{''} (t) - 6 y^{'} (t) - 16 y = 0

Solve linear ODE:

y = c_{1} e^{8 t} + c_{2} e^{- 2 t}

y = c_{1} e^{8 t} + c_{2} e^{- 2 t}

\frac{d}{d x} (4 x^{0.75} \cdot (240 - 2 x)^{0.5})

\int_{- 3}^{- 1} \frac{5}{x ^{4}} d x

n or ma l f (x) = \frac{27}{5 x ^{2}} - \frac{3}{2}, at x = 1

\int_{1}^{5} \frac{x ^{2} + 5}{6 x - x ^{2}} d x

y^{^{''}} + 2 π y^{^{'}} + π^{2} y = 0