What is the derivative of f(x)=x^2-sqrt(x+4) ?

The derivative of f(x)=x^2-sqrt(x+4) is 2x-1/(2sqrt(x+4))

What is the first derivative of f(x)=x^2-sqrt(x+4) ?

The first derivative of f(x)=x^2-sqrt(x+4) is 2x-1/(2sqrt(x+4))

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derivative of

f (x) = x^{2} - x + 4

2 x - \frac{1}{2 x + 4}

Solution steps

\frac{d}{d x} (x^{2} - x + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (x + 4)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (x + 4) = \frac{1}{2 x + 4}

= 2 x - \frac{1}{2 x + 4}

\frac{d}{d t} (cot^{4} (t) - csc^{4} (t))

x \to 4 lim (8 - 2 x)

x \to \infty lim (8^{x})

\int 8 x^{2} e^{x} d x

2 (x + 4)^{\frac{3}{2}}

What is the derivative of f(x)=x^2-sqrt(x+4) ?
The derivative of f(x)=x^2-sqrt(x+4) is 2x-1/(2sqrt(x+4))
What is the first derivative of f(x)=x^2-sqrt(x+4) ?
The first derivative of f(x)=x^2-sqrt(x+4) is 2x-1/(2sqrt(x+4))