integral of t-cos(t)

Lösung

\int t - cos (t) d t

\frac{t ^{2}}{2} - sin (t) + C

Schritte zur Lösung

\int t - cos (t) d t

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int t d t - \int cos (t) d t

\int t d t = \frac{t ^{2}}{2}

\int cos (t) d t = sin (t)

= \frac{t ^{2}}{2} - sin (t)

Füge eine Konstante zur Lösung hinzu

= \frac{t ^{2}}{2} - sin (t) + C

\frac{d}{d x} (\frac{3 x ^{2} - 18 x + 25}{x ^{2} - 6 x + 8})

\int \frac{4 x - 2}{( 4 x ^{2} - 4 x + 2 ) ^{4}} d x

in v erse l a pl a ce \frac{1 - e ^{- 2 s}}{6 s ^{2}}

x \to 0 lim (- cos (x) + 1)

y = x (1 - x)^{6}