What is the integral of-3/5 e^x ?

The integral of-3/5 e^x is -3/5 e^x+C

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integral of-3/5 e^x

\int - \frac{3}{5} e^{x} d x

- \frac{3}{5} e^{x} + C

Solution steps

\int - \frac{3}{5} e^{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{3}{5} \cdot \int e^{x} d x

Use the common integral:

\int e^{x} d x = e^{x}

= - \frac{3}{5} e^{x}

Add a constant to the solution

= - \frac{3}{5} e^{x} + C

\int 4 - 6 x - 40 x^{3} d x

\int_{0}^{2} 1 + e^{- 2 x} d x

n = 1 \sum \infty \frac{3}{( - 2 ) ^{n}}

\int_{0}^{\infty} \frac{1}{5 + x} d x

d er i v a t i v e f (x) = x^{2}