xy^'sin^2(y/x)=x+ysin^2(y/x)

Lösung

x y^{^{'}} sin^{2} (\frac{y}{x}) = x + y sin^{2} (\frac{y}{x})

y = - W (- \frac{1}{c _{1} x}) x

Schritte zur Lösung

x y^{'} (x) sin^{2} (\frac{y}{x}) = x + y sin^{2} (\frac{y}{x})

Solve using substitution:

y = - W (- \frac{1}{c _{1} x}) x

y = - W (- \frac{1}{c _{1} x}) x

\frac{\partial}{\partial x} (8 y^{7} cos (8 x))

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x \to 2 lim (\frac{3}{x ^{2} - 4})

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