What is the sum from n=1 to infinity of (n+1)/(2n+1) ?

The sum from n=1 to infinity of (n+1)/(2n+1) is diverges

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sum from n=1 to infinity of (n+1)/(2n+1)

n = 1 \sum \infty \frac{n + 1}{2 n + 1}

diverges

Solution steps

n = 1 \sum \infty \frac{n + 1}{2 n + 1}

Apply Series Divergence Test:

diverges

= diverges

d er i v a t i v e y = x^{3 \cdot 7}

d er i v a t i v e f (x) = \frac{( x ^{2} - 3 x )}{2}

\frac{\partial}{\partial x} (x^{2} + y^{2} + x y + 3)

\frac{d y}{d x} = \frac{x ^{2} - 9}{x}

\int_{0}^{3} x e^{- 4 x} d x

What is the sum from n=1 to infinity of (n+1)/(2n+1) ?
The sum from n=1 to infinity of (n+1)/(2n+1) is diverges