limit as x approaches 1 of ln|x-1|

Lösung

x \to 1 lim (ln ∣ x - 1 ∣)

- \infty

Schritte zur Lösung

x \to 1 lim (ln ∣ x - 1 ∣)

Wenn

x \to a - lim f (x) = x \to a + lim f (x) = L

dann

x \to a lim f (x) = L

x \to 1 - lim (ln ∣ x - 1 ∣) = - \infty

x \to 1 + lim (ln ∣ x - 1 ∣) = - \infty

= - \infty

\frac{\partial ^{2}}{\partial x ^{2}} (2 cos (x y^{2}))

(\frac{d y}{d x}) = (x + y + 7)^{2}

- \frac{x 1 - y ^{2}}{y 1 - x ^{2}} = \frac{d y}{d x}

n = 0 \sum \infty \frac{n ^{2} + 1}{n !}

\frac{d}{d u} (\frac{u - 1}{u + 1})