What is the tangent of f(x)=16sqrt(x),(16,64) ?

The tangent of f(x)=16sqrt(x),(16,64) is y=2x+32

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tangent of f(x)=16sqrt(x),(16,64)

tangent of

f (x) = 16 x, (16, 64)

y = 2 x + 32

Solution steps

Find the slope of

f (x) = 16 x : \frac{df ( x )}{d x} = \frac{8}{x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 2

Find the line with slope m=

2

and passing through

(16, 64) : y = 2 x + 32

y = 2 x + 32

\int \frac{1}{1 - 3 x} d x

d er i v a t i v e f (t) = \frac{5 t ^{2} + t + 6}{t}

\int \frac{7 x}{( 1 - x ^{2} ) ^{3}} d x

x \to π lim (\frac{cos ( x )}{x})

y^{^{'}} = 2 x y + 3 y - 4 x - 6

What is the tangent of f(x)=16sqrt(x),(16,64) ?
The tangent of f(x)=16sqrt(x),(16,64) is y=2x+32