limit as x approaches-1 of 1/(x+1)

解答

x \to - 1 lim (\frac{1}{x + 1})

发散

求解步骤

x \to - 1 lim (\frac{1}{x + 1})

若

x \to a^{-} lim f (x) \neq = x \to a^{+} lim f (x)

则极限不存在

x \to - 1 + lim (\frac{1}{x + 1}) = \infty

x \to - 1 - lim (\frac{1}{x + 1}) = - \infty

= 发散

x \to 0 lim (e^{7 x})

\int arccos (7 x) d x

n = 0 \sum \infty n + 2

\frac{d x}{d t} = - 2 x - 3 x^{2}

d er i v a t i v e (cos^{2} (s) - 4 s^{2})^{2}