What is the derivative of ln(4+x) ?

The derivative of ln(4+x) is 1/(4+x)

What is the first derivative of ln(4+x) ?

The first derivative of ln(4+x) is 1/(4+x)

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\frac{d}{d x} (ln (4 + x))

\frac{1}{4 + x}

Solution steps

\frac{d}{d x} (ln (4 + x))

Apply the chain rule:

\frac{1}{4 + x} \frac{d}{d x} (4 + x)

= \frac{1}{4 + x} \frac{d}{d x} (4 + x)

\frac{d}{d x} (4 + x) = 1

= \frac{1}{4 + x} \cdot 1

Simplify

= \frac{1}{4 + x}

\int x e^{x} - e^{x} d x

\frac{d y}{d x} = 2 x y + \frac{6}{π}

\int \frac{1}{x ^{4} 9 - x ^{2}} d x

\frac{d y}{d t} = \frac{1}{2} t

y^{^{''}} + 6 y^{^{'}} + 9 y = 12 e^{- 3 x}

What is the derivative of ln(4+x) ?
The derivative of ln(4+x) is 1/(4+x)
What is the first derivative of ln(4+x) ?
The first derivative of ln(4+x) is 1/(4+x)