What is the xln(x)=y(1+sqrt(24+y^2))y^'(x),y(1)=1 ?

The xln(x)=y(1+sqrt(24+y^2))y^'(x),y(1)=1 is y'(x)+y'(x)sqrt(24+y^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

xln(x)=y(1+sqrt(24+y^2))y^'(x),y(1)=1

x ln (x) = y (1 + 24 + y^{2}) y^{^{'}} (x), y (1) = 1

y' (x) + y' (x) 24 + y^{2}

Solution steps

Find

y (1 + 24 + y^{2}) y^{'} (x)

given

y (1) = 1

y (1 + 24 + y^{2}) y^{^{'}} (x) = y (1 + 24 + y^{2}) y^{^{'}} (x)

y : 1

24 + y^{2} : 24 + 1^{2}

= 1 \cdot (1 + 24 + y^{2}) y^{^{'}} (x)

Expand

1 \cdot (1 + 24 + y^{2}) y^{'} (x) : y^{'} (x) + y^{'} (x) 24 + y^{2}

= y^{'} (x) + y^{'} (x) 24 + y^{2}

\int (2 x + 2) d x

d er i v a t i v e f (x) = x^{n}

n = 0 \sum \infty (\frac{1}{2})^{n}

\frac{\partial}{\partial x} (1.2 x^{0.6} y^{0.4})

t a y l or sin (x - \frac{π}{4})

What is the xln(x)=y(1+sqrt(24+y^2))y^'(x),y(1)=1 ?
The xln(x)=y(1+sqrt(24+y^2))y^'(x),y(1)=1 is y'(x)+y'(x)sqrt(24+y^2)