What is the limit as x approaches+0 of (e^{x^2}-1)/x ?

The limit as x approaches+0 of (e^{x^2}-1)/x is 0

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limit as x approaches+0 of (e^{x^2}-1)/x

x \to + 0 lim (\frac{e ^{x^{2}} - 1}{x})

0

Solution steps

x \to 0 lim (\frac{e ^{x^{2}} - 1}{x})

Apply L'Hopital's Rule

= x \to 0 lim (\frac{2 e ^{x^{2}} x}{1})

Plug in the value

x = 0

= \frac{2 e ^{0^{2}} \cdot 0}{1}

Simplify

\frac{2 e ^{0^{2}} \cdot 0}{1} : 0

= 0

\frac{d}{d x} (\frac{x ^{2} + 25}{x})

\frac{\partial}{\partial z} (ln (1 + z^{2}))

\int - \frac{6000}{( 3 x + 50 ) ^{2}} d x

x \to 15 lim (2)

t a y l or e^{2 x}, 1

What is the limit as x approaches+0 of (e^{x^2}-1)/x ?
The limit as x approaches+0 of (e^{x^2}-1)/x is 0