en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular Calculus >

y^{''}-2y^'+y=1

Solution

y^{^{''}} - 2 y^{^{'}} + y = 1

Solution

y = c_{1} e^{t} + c_{2} t e^{t} + 1

Solution steps

y^{''} (t) - 2 y^{'} (t) + y = 1

Solve linear ODE:

y = c_{1} e^{t} + c_{2} t e^{t} + 1

y = c_{1} e^{t} + c_{2} t e^{t} + 1

Graph

Popular Examples

(dy)/(dx)=(x^2+y^2)/(yx)

\frac{d y}{d x} = \frac{x ^{2} + y ^{2}}{y x}

derivative of ln(x+9)

d er i v a t i v e ln (x + 9)

limit as t approaches 0 of e^{-3t}

t \to 0 lim (e^{- 3 t})

derivative of ax^2e^{4x}

\frac{d}{d x} (a x^{2} e^{4 x})

area y=x,y=(6.75x)/(x^2+1)

a re a y = x, y = \frac{6.75 x}{x ^{2} + 1}

Frequently Asked Questions (FAQ)

What is the solution for y^{''}-2y^'+y=1 ?
The solution for y^{''}-2y^'+y=1 is y=c_{1}e^t+c_{2}te^t+1