What is the solution for e^x(dy)/(dx)=e^{-y}+e^{2x-y} ?

The solution for e^x(dy)/(dx)=e^{-y}+e^{2x-y} is y=ln(-e^{-x}+e^x+c_{1})

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e^x(dy)/(dx)=e^{-y}+e^{2x-y}

e^{x} \frac{d y}{d x} = e^{- y} + e^{2 x - y}

y = ln (- e^{- x} + e^{x} + c_{1})

Solution steps

e^{x} \frac{d y}{d x} = e^{- y} + e^{2 x - y}

Solve separable ODE:

y = ln (- e^{- x} + e^{x} + c_{1})

y = ln (- e^{- x} + e^{x} + c_{1})

cos (x), sin (x)

2 x^{2} y^{^{''}} + 3 x y^{^{'}} = y

2 cos (7 x), 2 - 2 cos (7 x), 0 \leq x \leq \frac{π}{7}

\int_{0}^{1} e^{- s t} \cdot t d t

\int e^{- 4 t} d t

What is the solution for e^x(dy)/(dx)=e^{-y}+e^{2x-y} ?
The solution for e^x(dy)/(dx)=e^{-y}+e^{2x-y} is y=ln(-e^{-x}+e^x+c_{1})