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tangent f(x)=x^2-3x+5,\at x=1

解答

切线

f (x) = x^{2} - 3 x + 5, at x = 1

解答

y = - x + 4

求解步骤

找到切点:

(1, 3)

计算

f (x) = x^{2} - 3 x + 5

的斜率:

\frac{df ( x )}{d x} = 2 x - 3

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 1

找到斜率 m=

- 1

且穿过

(1, 3)

的直线:

y = - x + 4

y = - x + 4

作图

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