-18y^{''}-14y^'=0,y(3)=-3,y^'(3)=-3

Lösung

- 18 y^{^{''}} - 14 y^{^{'}} = 0, y (3) = - 3, y^{^{'}} (3) = - 3

y = \frac{27 e ^{\frac{7}{3}}}{7} e^{- \frac{7 t}{9}} - \frac{48}{7}

Schritte zur Lösung

- 18 y^{''} (t) - 14 y^{'} (t) = 0

Solve linear ODE:

y = \frac{27 e ^{\frac{7}{3}}}{7} e^{- \frac{7 t}{9}} - \frac{48}{7}

y = \frac{27 e ^{\frac{7}{3}}}{7} e^{- \frac{7 t}{9}} - \frac{48}{7}

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