laplacetransform-8e^{pi-t}

Lösung

laplace transformation

- 8 e^{π - t}

- \frac{8 e ^{π}}{s + 1}

Schritte zur Lösung

L {- 8 e^{- t + π}}

Verwende die konstante Multiplikationseigenschaft der Laplace-Transformation:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= - 8 e^{π} L {e^{- t}}

L {e^{- t}} : \frac{1}{s + 1}

= - 8 e^{π} \frac{1}{s + 1}

Fasse

- 8 e^{π} \frac{1}{s + 1}

zusammen:

- \frac{8 e ^{π}}{s + 1}

= - \frac{8 e ^{π}}{s + 1}

d er i v a t i v e (x^{3} + 2 x^{2})^{- 1}

n = 1 \sum \infty arctan (n + 1)

z \to i lim (z (z + 1))

\frac{d}{d x} (\frac{1}{ln ^{2} ( x )})

\int \frac{1}{x 9 x ^{2} + 16} d x